$re = '/^.*?(\S+)$/m';
$str = 'Austria: ac.at
Bangladesh: ac.bd
Belgium: ac.be
China: ac.cn
Cyprus: ac.cy
India: ac.in';
$subst = "$Resolved URL$ LIKE \"*$1/*\"";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php