using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @".*[a-zA-Z.].*(*SKIP)(*FAIL)|\B(?=(\d{3})+(?!\d))";
string substitution = @",";
string input = @"Good
1
23
123
1234
12345
752892
1234567
Bad
123123456.000000
12a3123456.0000000000
123456.12345a12345";
RegexOptions options = RegexOptions.Multiline;
Regex regex = new Regex(pattern, options);
string result = regex.Replace(input, substitution);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx