import re
regex = re.compile(r"\n (\d)", flags=re.MULTILINE)
test_str = ("\n"
" this \n"
" 1. is \n"
" 2. some \n"
" 3. text \n")
subst = "\\1"
result = regex.sub(subst, test_str)
if result:
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html