re = /6\/([1-9]|1[0-9]|2[0-9]|30)\/[0-9]{2}$|^[7-8]\/([1-9]|1[0-9]|2[0-9]|3[0-1])\/[0-9]{2}/m
str = 'col5date
7/4/22
8/29/22
10/9/22
12/12/20
9/1/19
9/1/22
9/22/19
2/16/22
6/16/22'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html