re = /\d{12,14}/m
str = '11 digit string: 12345678901
12 digit string: 123456789012
13 digit string: 1234567890123
14 digit string: 12345678901234
15 digit string: 123456789012345'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html