re = /(\s\b(\d*[a-z]\d*){1,2}\b)|(\s\b\d+\b)/
str = 'abcd abc ad1r ab a11b a1 11a 1111 1111abcd'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html