re = /\b([1-9](?:\s*[0-9]){3})\s?([A-Z])(?i:\2*)\s*([A-Z])(?i:\3*)\b/m
str = '1 2 3 4 Alpha Bravo
1234 Alpha Bravo
1234A Bbbbbbbc
1234Aaa Bbb
1234Aa Bbb
1234A BbbbBbbbb'
subst = '$1$2$3'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html