re = /^[a-zA-Z\d-]{1,100}/m
str = 'RE-1234-56-789-0
123-AB-12-INV
123456789
ABCDE
2019-01-19-ABCD
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html