re = /^[v]((\d?\d\.)(0\.|[1-9]?[0-9]\.)([1-9]?[0-9]|))$/m
str = 'v0.1.2
v12.1.0
v0.0.1
v0.12.0
v10.10.10
10.10.10
v222.10.0
v0.999.0
v0.1.111
v0.01.0
v0.1.01
v12.1
v12'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html