re = /foo(?:\sbar)?(?:\sbaz)?|bar(?:\sbaz)?|baz/m
str = 'foo bar baz
foo baz bar
baz bar foo
foo bar
foo baz
bar baz
foo
bar
baz'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html