re = /([\d\(][\(\)\s\.\-\d]{4,}\d)/
str = 'whatever 0 (000) 000-0000 whatever whatever 0(000)000-0000 whatever
whatever (000) 000-0000 whatever whatever (000)000-0000 whatever
whatever 000 000-0000 whatever whatever 000.000.0000 whatever
whatever 000-42000-0000 whatever whatever 000-0000 whatever
whatever 000 - 0000 whatever whatever 000.0000 whatever
whatever 000 . 0000 whatever whatever 000 0000 whatever 1
whatever 00000000000 whatever
whatever 0000000000 whatever
whatever 000000000 whatever
whatever 00000000 whatever
whatever 0000000 whatever
whatever 000000 whatever
whatever 00 00 0000 0000 whatever 3
whatever 00 0000 000 000 whatever 3
whatever 000 0000 0000 whatever 2
whatever (000) 0000 0000 whatever
whatever 00000 000000 whatever 1
whatever 00 0000 0000 whatever 21135'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html