re = /^(?>\S+[^\S\n]+){3,}?(\S+?)\K\1(?!\S)/m
str = '00101 blah 0000202 thisisasentencethisisasentence 99929
00102 blah 0000202 thisisasentenc1thisisasentenc1 999292'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html