import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = #"([0-9]{1,2})\s*([\u0400-\u04FF]+)\s*([0-9]{4}|[0-9]{2})|([0-9]{1,2})\s*(j|f|m|a|j|s|o|n|d[a-z.]+)\s*([0-9]{4}|[0-9]{2})|([0-9]{1,2})\s*[./]{1}\s*([0-9]{1,2})\s*[./]{1}\s*([0-9]{4}|[0-9]{2})"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive])
let testString = #"""
14ДекабрЯ 2017, 20: 05, вопрос № 1846141, г. Омск
Ответ 3 dec.97, 20: 05, вопрос № 1846141, г. Омск
Дата написания 15 марта 2011, 15:02 а следующая дата 23 . 06. 19
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression