import Foundation
let pattern = #"(?<hora>[0-9]{8})\s(?<mix>\d{3})(?<resp>[I|O])"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
09523744 865O F010@@@@Y1905A46100000002 00000000151100157600STD20001
865O 030202040005 1029 003047100000000012602
865O 00000000000000000000000000000000000000000000517712002534
865O 4898
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression