const regex = new RegExp('^.*[^\\d\\r\\n](\\d+)', 'gm')
const str = `2^64
asdgaf1_hsg534
asdfh23_hsjd12
dgshg_jhfsd86
test
1
testing 1234 testing 1 test4
testing 1234 testing 123`;
const subst = `\1`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions