$re = '/\'(?:\.+\/)*([^\']+)\'/m';
$str = '\'./components/chunks/breadcrumbs/breadcrumbs.html\'
\'../../components/chunks/breadcrumbs/breadcrumbs.html\'
\'./../../components/chunks/breadcrumbs/breadcrumbs.html\'
\'../../../components/chunks/breadcrumbs/breadcrumbs.html\'
\'./../../../components/chunks/breadcrumbs/breadcrumbs.html\'
\'../../../../components/chunks/breadcrumbs/breadcrumbs.html\'
При любом уровне вложенности нужно получить
components/chunks/breadcrumbs/breadcrumbs.html';
$subst = "$1";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php