# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"^([A-Z]\d{1,2}|[A-Z]{2}\d(\d|[A-Z])?)( \d[A-Z]{2})?$"
test_str = ("1 Letter 1 Number\n"
"E2\n"
"1 Letter 2 Numbers\n"
"E22\n"
"2 Letters 1 Number\n"
"EE2\n"
"2 Letters 1 Number 1 Letter\n"
"EE2E\n"
"2 Letters 2 Numbers\n"
"EE22\n"
"1 Letter 1 Number (Space) 1 Number 2 Letters\n"
"E2 2EE\n"
"1 Letter 2 Numbers (Space) 1 Number 2 Letters\n"
"E22 2EE\n"
"2 Letters 1 Number (Space) 1 Number 2 Letters\n"
"EE2 2EE\n"
"2 Letters 1 Number 1 Letter (Space) 1 Number 2 Letters\n"
"EE2E 2EE\n"
"2 Letters 2 Numbers (Space) 1 Number 2 Letters\n"
"EE22 2EE\n\n"
"6FW OX28\n"
"82XO 6FW\n"
"OX28 6FW\n\n"
"E2E\n"
"E22E\n"
"E33 33E")
matches = re.finditer(regex, test_str, re.MULTILINE | re.IGNORECASE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html