re = /(\d+(?:[\.,](?![\.,])\d+)*)/
str = '1,23...233
.8.8,0
,9..9,9
6,234
1234
1,234
1,234.00
1234..00
1,234,456.789
1,2345hgf456...789'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html