re = /IP (?:\d+|\.|[a-z]()){7}\1[^\n]+/m
str = 'IP bt.ru.https > 192.168.88.10.54276: tcp 3374
IP 192.168.88.10.54276 > 192.168.88.18.https: tcp 0
IP 192.168.88.10.54276 > 192.168.88.18.https: tcp 0
IP 192.168.88.10.54276 > 192.168.88.18.https: tcp 0
IP somedomain.ru.https > 192.168.88.10.54276: tcp 334
IP 192.168.88.10.54276 > 192.168.88.18.https: tcp 0
IP 192.168.88.10.54276 > 192.168.88.18.https: tcp 0
IP 192.168.88.10.54276 > 192.168.88.18.https: tcp 0
IP www.somedomain.ru.https > 192.168.88.10.54276: tcp 228'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html