re = /^(0[1-9]|[1-2][0-9]|3[0-1])\/(0[1-9]|1[0-2])\/(\d{4})$/m
str = '13/07/1993
01/01/1993
12/12/1955
31/12/1999
1/12/1999
31/12/19992
32/13/1955
42/11/1955
01/12/2000'
subst = ''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html