re = /^\.?\d{1,5}(?:\.\d{1,5})*$/m
str = '1
12
123
1234
12345
123456
1.2
.1
.1.2
1234567890
1234567890.
12345.67890
.1234567890
123.4567.890
.1234567890.
12345..67890
.1234.567890.
1.234.567.890
.123.456.7890
.1.2.3.4.5.6.7.8.9.0
.1.2.3.4.5.6.7.8.9.0.'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html