re = /0*(?|(1[10]{6})|([10]{6}1))/m
str = '10
1111100
1000000
11110000000
111111111111
000000001111
000011110000
00000000111100
000000001111000
0000000011110000'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html