import Foundation
let pattern = #""([^"]*)""#
let regex = try! NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let testString = ##"""
REQUIREMENT: Match strings between two identical characters
REGEX FIDDLE: https://regex101.com/r/BVjLuU/2
MATCH:
A "1" text "+" some more text, and "there can be ==1234== even more "text
in btw quotes
NO MATCH
text here, 1234.
FURTHER LINKS:
- Negated character class: https://www.regular-expressions.info/charclass.html#negated
- Capturing groups: https://www.regular-expressions.info/brackets.html
- Regex plus vs star difference SO question: https://stackoverflow.com/q/8575281/3832970
- Google for '<language> regex extract part of a match stackoverflow'
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression