re = /^(0(1|2|3|7|8|9)\d{9})|(0(1|55|56)\d{8})|(0800\d{6})$/m
str = '
01222222224
02111111111
03888888888
05544448888
05699995555
05899996666
07752300794
08585458745
09555888574
0169778888
0125478596
0163546835
0800222555
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html