re = /\d(?!\d{22})(102030)\d{10}/
str = '75277887243040354513001
55345377243014107206375
810203087654135168
1102030698798798477
71020307248040361799581'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html