re = /(^(([0]?[1-9])|([1-2][0-9])|(3[0-1]))\/(([0]?[1-9])|(1[0-2]))\/(\d{4}))$/m
str = '07/24/1969
01.01.1900
10/10/2017
1830/10/4
2/10/00
05-05-92
18/05/1804
6/30/1996
99/00/2000
06/12/1865
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html