import Foundation
let pattern = #"(A(\d{8})00|(A(\d{7})00))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
//Should match:
ABC12345678CRP1234567F2801209A1234567800<<<33
ABC12345678CRP1234567F2801209A123456700<<<33
//Should not match:
ABC12345678CRP1234567F2801209B1234567800<<<33 (starts with B)
ABC12345678CRP1234567F2801209A12345600<<<33 (less than 7 or 8 digits)
ABC12345678CRP1234567F2801209A1234567899<<<33 (ends with 99)
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression