$re = '/(^References:|\G(?!\A)).*?@\Kdomain-a\.com/m';
$str = 'References: <mail-1@domain-a.com> <mail-2@domain-a.com> <mail-3@domain-a.com>
Another-Header: <example@domain-a.com>
';
$subst = "domain-b.com";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php