re = /^\d+\t\K(.+?)(?=\t)/m
str = '2012 Mark Dept other
2010 Louanne Dept other
2009 Jannett Dept other'
subst = '[url=http://www.website.com/personell/$1]$1[/url]'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html