$re = '/(^.*\/).*/m';
$str = 'http://xxxx.com/xxx-xxx-xxx-xxxx/ 60% 2 Weekly 2014-01-01 00:00
http://somethingelse.com/123-456-789-0000/ 60% 2 Weekly 2014-01-01 00:00
http://anothersite.com/page/boop/beep/ 60% 2 Weekly 2014-01-01 00:00
http://baloogawhalesarenotaliens.com/ 60% 2 Weekly 2014-01-01 00:00
';
$subst = "$1";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php