re = /\bST(?:REET)?+\B/m
str = '703 6TH STREET SOUTHTEXAS CITY TX 77590
1201 WEST FRONT STREETCHESTER PA 19013-3496
1201 WEST FRONT STCHESTER PA 19013-3496
'
subst = '$0 '
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html