re = /(\d{5})[-. ](\d{6})/m
str = 'something 01234 567890 around
aaa 01111-222111 bbbb
cccc 09876.543210 ddd
'
subst = '(one:\\1) (two:\\2) (three:3)'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html