re = /^\+{0,2}\d+(?:\b \b|\d)+$/m
str = '+41 51 271 21 44
++51 271 21 44
++51 271 21 44
051 271 21 44
0512712144
0041512712144
051 271 21 44
051 271 21a44
0041 51 271 21 44
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html