re = /\d{4}(?!$)/m
str = '1111222233334444
111122223333444
11112222333344
1111222233334
111122223333
11111
9999'
subst = '$&-'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html