re = /(^\d{3}|(?<=^\d{3})\d{3}|\d+$)/m
str = '1234567899
12345678
1234567
123456
12345
123
1'
subst = '(\\1)'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html