import Foundation
let pattern = #"\([^)]*\)|\[[^\]]*\]"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
1. The (quick) brown [fox]
2. The (quick) (test) brown [fox] [more] (test) [test][test]
3. The (quick) brown [fox] The (quick) brown [fox] The (quick)
brown [fox] The (quick) brown [fox]
4. Hopefully, you [don't) have cases like (this].
5. Or this: (nesting (like this), need update to regex).
6. Or heterogeneous mixing: (Test [condition] )
If you have conditions 4, 5, 6. Please update your question!
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression