$re = '/((https:\/\/web.archive.org\/web\/\d*)(\/https?:\/\/?(www\.)?.*))/m';
$str = 'https://web.archive.org/web/20210709181138if_/https://www.cualquierdominio.es/slug/contenido.html
https://web.archive.org/web/20210709181138/http://www.dominioaceptable.com/slug/contenido.php
https://web.archive.org/web/20210709181138/http://dominiobaneado.co.uk/slug/contenido.html?id=324
https://web.archive.org/web/20210709181138/https://dominiosnuevos.info/slug
';
$subst = "$2if_$3";
$result = preg_replace($re, $subst, $str);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php