re = /(\d{9}) (\d{5})/m
str = '123456789 12345678
12345678 12345
123456789 123456
123456789 12345
123456789 AZERT'
subst = '$1$2'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html