use strict;
my $str = '\'\'\'
MATCH THE TEXT WITH ZERO, ONE OR NO DELIMITERS:
ADD MISSING OPENING AND/OR CLOSING DELIMITER
(NOTE: ALSO MATCHES WITH BOTH DELIMITERS)
sad
fsd
f
sdasdf
dsf
\'\'\'';
my $regex = qr/^(?:'''\n?)?((?:.*?)(?:\n.*?)*?)(?:\n?'''\n?)?$/p;
my $subst = '\'\'\'\\n$1\\n\'\'\'';
my $result = $str =~ s/$regex/$subst/rg;
print "The result of the substitution is' $result\n";
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Perl, please visit: http://perldoc.perl.org/perlre.html