re = /^(?:'''\n?)?((?:.*?)(?:\n.*?)*?)(?:\n?'''\n?)?$/
str = '\'\'\'
MATCH THE TEXT WITH ZERO, ONE OR NO DELIMITERS:
ADD MISSING OPENING AND/OR CLOSING DELIMITER
(NOTE: ALSO MATCHES WITH BOTH DELIMITERS)
sad
fsd
f
sdasdf
dsf
\'\'\''
subst = '\'\'\'\\n$1\\n\'\'\''
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html